Leumas Physics

Alpha Decay Kinetic Energy

E_alpha = Q_r·(A_n - 4)/A_n

What it says

The alpha particle carries most but not all of the released energy; the recoiling nucleus takes the rest.

Symbols

SymbolQuantityDimension
E_alphaAlpha kinetic energy (J)M L^2 T^-2
Q_rEnergy released (J)M L^2 T^-2
A_nParent nucleon count (dimensionless)1

Work it out

Enter what you know. No account needed.

Fill in all but one: Q_r, A_n, E_alpha are all empty.

Connects to

Filed under Nuclear · derive through it in the explorer