Flux from Luminosity
F = L / (4·π·d^2)
What it says
The power per unit area reaching us from a source of known luminosity at a known distance.
Symbols
| Symbol | Quantity | Dimension |
|---|---|---|
F | Radiant flux (W/m^2) | M T^-3 |
L | Luminosity (W) | M L^2 T^-3 |
d | Distance (m) | L |
Work it out
Enter what you know. No account needed.
Fill in all but one: L, d, F are all empty.
Connects to
Filed under Astrophysics · derive through it in the explorer