Projectile Maximum Height
H = (v0^2·sin(θ)^2) / (2·g)
What it says
Gives the maximum vertical height reached by a projectile launched at speed v0 and angle θ under gravity, neglecting air resistance.
Symbols
| Symbol | Quantity | Dimension |
|---|---|---|
v0 | Launch speed (m/s) | L T^-1 |
θ | Launch angle above horizontal (rad) | 1 |
H | Maximum height (m) | L |
Work it out
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Connects to
Filed under Mechanics · derive through it in the explorer