Relativistic Kinetic Energy
KE = (1 / sqrt(1 - v^2/c^2) - 1)·m·c^2
What it says
The kinetic energy of a relativistic particle is the difference between its total energy and its rest energy, equal to (gamma - 1)·m·c^2 with c = 299792458 m/s. It reduces to the classical (1/2)·m·v^2 at low speed.
Symbols
| Symbol | Quantity | Dimension |
|---|---|---|
KE | Kinetic energy (J) | M L^2 T^-2 |
m | Rest mass (kg) | M |
v | Speed (m/s) | L T^-1 |
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Filed under Relativity · derive through it in the explorer