Simple Pendulum Frequency
f = (1 / (2·π))·sqrt(g / L), g = 9.80665 m/s^2
What it says
In the small-angle approximation, the frequency of a simple pendulum is proportional to the square root of gravitational acceleration g (9.80665 m/s^2) divided by its length.
Symbols
| Symbol | Quantity | Dimension |
|---|---|---|
f | Frequency (Hz) | T^-1 |
L | Length (m) | L |
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Filed under Mechanics · derive through it in the explorer