SHM Frequency Of A Spring
f = (1 / (2·π))·sqrt(k / m)
What it says
The natural frequency of a mass on an ideal spring is proportional to the square root of the spring constant divided by the mass.
Symbols
| Symbol | Quantity | Dimension |
|---|---|---|
f | Frequency (Hz) | T^-1 |
k | Spring constant (N/m) | M T^-2 |
m | Mass (kg) | M |
Work it out
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Connects to
Filed under Mechanics · derive through it in the explorer